Math, asked by pranjalsoni721, 10 months ago

Do q 25 plsssss ...... Guyss.......

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Answered by bhagirathj557
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Step-by-step explanation:

Let the speed of good train be x and the speed of express train be y. It is given that y=x+20. Then ,time taken by good train to travel 1040 is 1040/x and time taken by express trian is 1040/(x+20). So,(1040/x)-(1040/(x+20))=26/10. So,1040(x+20-x)/x^+20x= 26/10. Now ,(40×20)/x^+20x=1/10. So,x^+20x-8000=0. So,x^+100x-80x-8000=0. So,x(x+100)-80(x+100)=0. So,x=80;-100. Hence speed of good train is 80km/h and speed of express train is 100km/h

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