Question

do question no. 9 part a b and c

Answer 1

Explanation:

(a) sin A = 9/41

sin A = P/H

using phythagores theorem

H² = P² + B²

(41)² = (9)² + B²

1681 = 81 + B²

1681 - 81 = B²

1600 = B²

B = 40

cos A = B/H

cos A = 40/41

tan A = P/B

tan A = 9/40

(b) cosA = 3/5

cos A = B/H

using phythageores theorem

H² = P² + B²

(5)² = P² + (3)²

25 = P² + 9

25 - 9 = P²

16 = P²

P = 4

sin A = P/H

sin A = 4/5

tan A = P/B

tan A = 4/3

(c) sec A = 25/7

sec A = H/B

using pythageores theorem

H² = P² + B²

(25)² = P² + (7)²

625 = P² + 49

625 - 49 = P²

576 = P²

P = 24

tan A = P/B

tan A = 24/7

cosec A = H/P

cosec A = 25/24