Do question number 32222222222
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first find AC by Pythagoras theorem on finding AR = 10 then use this-
tangents to a circle from a same point are equal . let AP be y QC be x :.BQ =6 -x = BP =8-Y :.6-X =8-Y----(1)
now AP = Y=AR =10 - RC as RC = X :.Y= 10-X-----(2)
NOW SOLVE IT SIMULTANEOUS EQUATIONS
tangents to a circle from a same point are equal . let AP be y QC be x :.BQ =6 -x = BP =8-Y :.6-X =8-Y----(1)
now AP = Y=AR =10 - RC as RC = X :.Y= 10-X-----(2)
NOW SOLVE IT SIMULTANEOUS EQUATIONS
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