Question

do same as this:-
Question:-

ΔABC is an isosceles triangle in which ∠C= 90° . If AC = 6 cm, then AB=
A. 6√2 cm
B. 6 cm
C. 2√6 cm
D. 4√2cm

Answer:-

In triangle ABC
Let tge altitude be AD on BC

AC=25cm
AB=25cm
BC=14cm

Therefore DC= 1/2*BC
=1/2*14
=7

By Pythagoras theorem,
AD^2+CD^2=AC^2

AD^2+7^2=25^2

AD^2+49=625

AD^2=625-49

AD^2=576

AD=24

Therefore altitude from A on BC is 24 cm

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Answer 1

Answer:

In triangle ABC

Let tge altitude be AD on BC

AC=25cm

AB=25cm

BC=14cm

Therefore DC= 1/2*BC

=1/2*14

=7

By Pythagoras theorem,

AD^2+CD^2=AC^2

AD^2+7^2=25^2

AD^2+49=625

AD^2=625-49

AD^2=576

AD=24

Therefore altitude from A on BC is 24 cm

Answer 2

Answer:

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