Math, asked by vidhatakumar, 11 months ago

do sankhyao ka yog 36 hai aur unke hcf aur lcm 3 aur 105 hai un do sankhyao ke vyutkramo ka yog kya hoga​

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Answered by deepsen640
3

HELLO DEAR FRIEND

LET THE NUMBERS BE X AND Y

ATQ,

X + Y = 36

X = 36 - Y... (1)

ALSO GIVEN HCF ANF LCM = 3 AND 105

WE KNOW THAT

HCF × LCM = PRODUCT OF THE TWO NUMBERS.

THEN,

XY = 105 × 3

XY = 315

FROM EQN (1) PUTTING THE VALUE OF X.

(36 - Y)Y = 315

36Y - Y² = 315

36Y - Y² - 315 = 0

Y² - 36Y + 315 = 0

Y² - 21Y - 15Y + 315 = 0

Y(Y - 21) - 15(y - 21)

(y - 15)(y - 21)

Y = 15 , 21

IF Y = 15

FROM EQN (1) X = 36 - Y

X = 39 - 15

X = 24

IF Y = 21

THEN,

X = 36 - 21

X = 15

SO, X = 24 , 15

Y = 15 , 21

HOPE IT HELPS YOU DEAR FRIEND THANKS


vidhatakumar: wrong answer
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