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Answer:
Let the radius of the circles be r1
and r2,
So, r +2 = 12 =
r2 = 12-r1
Sum of the areas of the circles =74π
=>πr1²+ πR1²= 74π
=>r12+r2²= 74
=> I2+ (12- r1)² = 74
=>r1²+144-24r1 + r1² = 74
=>2r1²-24r1 +70=0
=>r1²-12r1+35 = 0
=>(r1-7)(r1-5) = 0
=> (r1-7)(r1-5)=0
=> r1=7 or r1 =5
Ir r1= 7 cm, then r2=5 cm
If r1=5 cm, then r2 = 7 cm
So, the diameters of the circles will
10 cm and 14 cm.
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