Question

do the answer of the question fast ​

Answer 1

Step-by-step explanation:

$\tt \dfrac{4x-2}{3}- \dfrac{23}{3}=13-5(\dfrac{7x+5}{3})$

$\tt \implies \dfrac{4x-2-23}{3}=13- \dfrac{35x-25}{3}$

$\tt \implies \dfrac{4x-25}{3}= \dfrac{39-35x-25}{3}$

$\tt \implies \dfrac{4x-25}{3}= \dfrac{14-35x}{3}$

$\tt \implies 3(4x-25)=3(14-35x)$

$\tt \implies 12x-75=42-105x$

$\tt \implies 12x+105x=75+42$

$\tt \implies 117x=117$

$\tt \implies x= \dfrac{117}{117}$

$\tt \implies x= 1$

Hope it helps....

Answer 2

$\dfrac{4x - 2}{3} - \dfrac{23}{3} \: = 13 - 5( \dfrac{7x + 5}{3} )$

$= > \: \dfrac{4x - 2 - 23}{3} \: = 13 - \dfrac{35x +25}{3}$

$= > \: \dfrac{4x - 25}{3} \: = \dfrac{39 - 35x - 25}{3}$

=>4x-25=14-35x

=>4x+35x=14+25

=>39x=39

=>x=39/39=1

so value of x is 1