Physics, asked by vanshikasharma3099, 9 months ago

do the differentiation
10 x ²-27x +5=0
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Answers

Answered by Anonymous
1

Answer:

10x²-27x+5=0

x=-b±√b²-4ac/2a ….in this 2a is common for both the terms

x=-(-27)±√(-27)²-4(10)(5)/2(10)

x=27±√729–200/20

x=27±√529/20

x=27±23/20

x=27+23/20,27–23/20

x=50/20,4/20

x=5/2,1/5

Explanation:

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