do the equation 3x+6y=2 and 6x+12y=4 represent a pair of consistent lines ?
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Hi ,
3x + 6y -2 = 0 ----( 1 )
6x + 12y - 4 = 0----( 2 )
Compare ( 1 ) and ( 2 ) with
a1x + b1y + c1 = 0,
a2 x + b2 y + c2 = 0 we get,
a1 = 3 , b1 = 6 , c1 = -2 ;
a2 = 6 , b2 = 12 , c2 = - -4
a1/a2 = 3/6 = 1/2
b1 / b2 = 6/12 = 1/2
c1 / c2 = ( -2 ) / ( - 4 ) = 1/2
Therefore ,
a1/a2 = b1/b2 = c1 / c2 = 1/2
Above system of equations are ,
dependent lines ,
Coincidendental lines .
Have infinitely many solutions.
I hope this helps you.
:)
3x + 6y -2 = 0 ----( 1 )
6x + 12y - 4 = 0----( 2 )
Compare ( 1 ) and ( 2 ) with
a1x + b1y + c1 = 0,
a2 x + b2 y + c2 = 0 we get,
a1 = 3 , b1 = 6 , c1 = -2 ;
a2 = 6 , b2 = 12 , c2 = - -4
a1/a2 = 3/6 = 1/2
b1 / b2 = 6/12 = 1/2
c1 / c2 = ( -2 ) / ( - 4 ) = 1/2
Therefore ,
a1/a2 = b1/b2 = c1 / c2 = 1/2
Above system of equations are ,
dependent lines ,
Coincidendental lines .
Have infinitely many solutions.
I hope this helps you.
:)
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