do the following equations represent a pair of conicident lines? -2x-3y=1,6y+4x=-2
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Answer:
Step-by-step explanation: 2x - 3y - 2 = 0. 4x - 6y - 10 = 0. a1 =2 b1= -3 c1 = -2. a2 =4 b2= -6 c2 = -10. a1/a2 = b1/b2 = c1/c2.
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Solution:
-2x - 3y = 1 and 6y + 4x = -2
Eq. 1
-2x - 3y = 1
-3y = 2x + 1
y = -2x/3 - 1/3
slope, m = -2/3
y-intercept = -1/3
Eq.2
6y + 4x = -2
6y = -4x - 2
y = -4x/6 - 2/6 =
slope, m = -4/6 = -2/3
y-intercept = -2/6 = -1/3
Therefore, if each line in the system has the same slope and the same y-intercept, the lines are coincident.
Hope this will be helpful to you.
-2x - 3y = 1 and 6y + 4x = -2
Eq. 1
-2x - 3y = 1
-3y = 2x + 1
y = -2x/3 - 1/3
slope, m = -2/3
y-intercept = -1/3
Eq.2
6y + 4x = -2
6y = -4x - 2
y = -4x/6 - 2/6 =
slope, m = -4/6 = -2/3
y-intercept = -2/6 = -1/3
Therefore, if each line in the system has the same slope and the same y-intercept, the lines are coincident.
Hope this will be helpful to you.
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