Question

do the long division of
$x + 1when \: divided \: by \: x {}^{3} - 3x {}^{3} - 9x - 5$
Pls do with full steps
​

Answer 1

Step-by-step explanation:

$\\ \\ = > \frac{ {x}^{3} - 3 {x}^{3} - 9x - 5 }{x + 1} \\ \\ \\ \\ = > \frac{ - 2 {x}^{3} - 9x - 5}{x + 1} \\ \\ so.... \\ \\ \\ \\ x + 1) - 2 {x}^{3} - 9x - 5( - 2 {x}^{2} + 2x - 11\\ \: \: \: \: \: \: \: \: \: \: \: - 2 {x}^{3} - 2 {x}^{2} \\ = = = + = = + = = = = = = = = \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2 {x}^{2} - 9x \\ \: \: \: \: \: \: \: \: \: \: \: \: \: 2 {x}^{2} + 2x \\ = = = {}^{ - } = = {}^{ - } = = = = = = = \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - 11x - 5 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - 11x - 11 \\ = = = = = = {}^{ + } = = = {}^{ + } = = = = = = = \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: + 6$

please mark me brainlist ✔️✔️

Answer 2

Answer:

$\begin{array}{ccccccccccc} & & x^2 & -4x & -5 \\\cline{3-10}\multicolumn{2}{r}{x+1 \surd}& x^3 &-3x^2 & -9x & -5 \\& &x^3 &+x^2 \\\cline{3-7}& & &-4x^2&-9x^ & & & & & \\& & &-4x^2& -4x \\\cline{4-8}& & & & 5x&-5 \\& & & &5x & -5\\\cline{5-9}&&&&&0 \\\end{array}$

The latex has shown us the division. Please open in browser (web) to see this answer. See in https://brainly.in/question/19190991. You can use any browser, chrome or opera.

Therefore,

$\sf \therefore \dfrac{x^3-3x^2-9x-5 }{ x+1} = x^2-4x-5$