Do the points (3.2).(-2.-3) and (2, 3) form a triangle?
Answers
Step-by-step explanation:
Let us apply the distance formula to find the distances PQ, QR and PR, where P(3, 2), Q(–2, –3) and R(2, 3) are the given points. We have Since the sum of any two of these distances is greater than the third distance, therefore, the points P, Q and R form a triangle. Also, PQ2 + PR2 = QR2, by the converse of Pythagoras theorem, we have ∠P = 90°. Therefore, PQR is a right triangle.Read more on Sarthaks.com - https://www.sarthaks.com/255565/do-the-points-3-2-2-3-and-2-3-form-a-triangle-if-so-name-the-type-of-triangle-formed
Step-by-step explanation:
Let the points be A(3,2) al, B(-2,-3) and C(2,3)
Now by distance formula
AB = √(3-(-2))^2 + (2-(-3))^2 = √(5)^2 + (5)^2
=√25+25 =√50=7.07
BC =√ (-2-2)^2+(-3-3)^2 = √(-4)^2 + (-6)^2 =√16+36
=√52 =7.21
AC=√(3-2)^2 + (2-3)^2 =√(1)^2+(-1)^2 =√1+1 =√2
=1.41
Since,sum of any 2 sides is greater than 3rd :. ABC is a triangle