Question

do the points (3 2) (-2 -3) and (2 ,3) form a triangle? if so, name the type of triangle formed. find a relation between xy such that the point (x,y) is equidistant from the point (7,1) and (3,5)​

Answer 1

Answer:

Let the points be A(3,2), B((-2,-3), C(2,3)

The distance AB =√{(3--2)^2+(2--3)^2}=5√2

Similarly BC=2√13

CA=√2

It is seen BC^2= AB^2+CA^2

(2√13)^2=(5√2)^2+(√2)^3

So the points form a right angle triangle with right angle at B

2nd part:

(x-7)^2+(y-1)^2=(x-3)^2+(y-5)^2

-8x+8y=0

x=y is the relationship