Question

Do the sum in a page and send the picture I will mark the correct answer as brainlist​

Answer 1

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$<font color="Purple">$

$<font size="3">$

$\huge{\boxed{\boxed{HEY}}}$

$<font color="Black">$

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$\bold\red{♡FollowMe♡}$

$<font color="blue">$

$\huge\underline\mathscr{Answer}$

$<font color="Black">$

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$<marquee direction="down" bgcolor="black">$

⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️

$</marquee>$

In rhombus...

Diagonals intersect each other at 90°

=> POQ = 90°

POQ + QPO + PQO = 180° (sum of angles of triangle)

PQO + 70 + 90 = 180

PQO = 20°

PQO = PQS = 20°

Now we know diagonals of Rhombus bisect each other.

OS = QO

angle POS = angle POQ

PO=PO

By SSS conguerence rule...

triangle POS= POQ

By CPCT rule...

Angle PSO = PQO

Hemce

PSO = 20°

$<marquee direction="up" bgcolor="black">$

⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️

$</marquee>$

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...Hope it helps....

Answer 2

Answer:

In rhombus...

Diagonals intersect each other at 90°

=> POQ = 90°

POQ + QPO + PQO = 180° (sum of angles of triangle)

PQO + 70 + 90 = 180

PQO = 20°

PQO = PQS = 20°

Now we know diagonals of Rhombus bisect each other.

OS = QO

angle POS = angle POQ

PO=PO

By SSS conguerence rule...

triangle POS= POQ

By CPCT rule...

Angle PSO = PQO

Hemce

PSO = 20°