do the sum in proper method
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Step-by-step explanation:
in ∆PQR,
QRS is an external angel so
QRS= QPR+PQR
QRS = 35+30
QRS = 65 = TRS
In ∆TRS,
QTS is an external angle so
QTS= TRS +TSR
x= 65+30
x= 95
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Answer:
x = 95°
Step-by-step explanation:
In ∆PQR,
<TRS = <PQR + <QPR = 30° + 35° = 65°
(ext. angle is equal to the sum of two int. opposite angles)
In ∆RST,
<QTS = <TRS + <TSR = 65° + 30° = 95°
(ext. angle is equal to the sum of two int. opposite angles)
And <QTS = x = 95°
My answer is not present in given options of your question
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