Question

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(1)
Ifp(x)=x2–5x-6, then find the values of p(1), p(2), p(3), p(0),p(-1),p(-2), p(-3).​

Answer 1

Step-by-step explanation:

p(x)=x²-5x-6

p(1)=(1)²-5(1)-6=-10

p(2)=(2)²-5(2)-6=-12

p(3)=(3)²-5(3)-6=-12

p(0)=(0)²-5(0)-6=-6

p(-1)=(-1)²-5(-1)-6=0

p(-2)=(-2)²-5(-2)-6=8

p(-3)=(-3)²-5(-3)-6=18