Math, asked by safiya10dgs18080041, 3 months ago

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6p(x)= x2 – 5x – 6, find the values of p(1), p(2), p(3), p(0),p(-1), p(-2), p(-3).
(i) p(m) = m2 – 3m +1, find the value of p(1) and p(-1).​

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Answered by creatorssheen
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  • Answer:

Answer:(i)p(1)=-1 p(-1)=3

  • Answer:(i)p(1)=-1 p(-1)=3Step-by-step explanation:

Answer:(i)p(1)=-1 p(-1)=3Step-by-step explanation:p(m)=m2-3m+1

Answer:(i)p(1)=-1 p(-1)=3Step-by-step explanation:p(m)=m2-3m+1p(1)=1-3+1

Answer:(i)p(1)=-1 p(-1)=3Step-by-step explanation:p(m)=m2-3m+1p(1)=1-3+1p(1)= -1

Answer:(i)p(1)=-1 p(-1)=3Step-by-step explanation:p(m)=m2-3m+1p(1)=1-3+1p(1)= -1p(-1)=1+3-1

Answer:(i)p(1)=-1 p(-1)=3Step-by-step explanation:p(m)=m2-3m+1p(1)=1-3+1p(1)= -1p(-1)=1+3-1p(-1)=3

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