Math, asked by RaGhAv200407, 1 year ago

Do this ASAP!! Pardon

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Answered by Anonymous
1
Hey mate ♥ here is ur answer
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RaGhAv200407: thank you
Answered by siddhartharao77
1

Answer:

9x² - 28x + 3

Step-by-step explanation:

Given Quadratic Equation is 3x² - 4x + 1.

Given that α,β are zeroes of the quadratic polynomial.

(i) Sum of roots:

α + β = -b/a

α + β = 4/3


(ii) Product of roots:

αβ = c/a

αβ = 1/3


We now desire quadratic polynomial whose zeroes are α²/β and β²/α.

(i) Sum of roots:

α²/β + β²/α

= (α³ + β³)/αβ

= [(α + β)³ - 3αβ(α + β)]/αβ

= [(4/3)³ - 3 * 1/3(4/3)]/1/3

= [64/27 - 4/3]/1/3

= 28/9


(ii) Product of roots:

⇒ α²/β * β²/α

⇒ αβ

⇒ 1/3


Hence, the required quadratic polynomial = x² - (28/9) x + 1/3

9x² - 28x + 3.


Hope it helps!


RaGhAv200407: thank you
siddhartharao77: Welcome :-)
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