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Hey mate ♥ here is ur answer
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RaGhAv200407:
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Answer:
9x² - 28x + 3
Step-by-step explanation:
Given Quadratic Equation is 3x² - 4x + 1.
Given that α,β are zeroes of the quadratic polynomial.
(i) Sum of roots:
α + β = -b/a
α + β = 4/3
(ii) Product of roots:
αβ = c/a
αβ = 1/3
We now desire quadratic polynomial whose zeroes are α²/β and β²/α.
(i) Sum of roots:
α²/β + β²/α
= (α³ + β³)/αβ
= [(α + β)³ - 3αβ(α + β)]/αβ
= [(4/3)³ - 3 * 1/3(4/3)]/1/3
= [64/27 - 4/3]/1/3
= 28/9
(ii) Product of roots:
⇒ α²/β * β²/α
⇒ αβ
⇒ 1/3
Hence, the required quadratic polynomial = x² - (28/9) x + 1/3
⇒ 9x² - 28x + 3.
Hope it helps!
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