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The upper point on a semicircle is always 90 degree
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Answer:
∠ODB = 52°
Step-by-step explanation:
Given --> ∠OCD = 52°
Now, we know that the diameter subtends a right angle anywhere in the circumference. So, ∠ CDB = 90°
Now, ∠OCD + ∠CDB + ∠DBC = 180° (Angle Sum Property of triangle)
=> 52° + 90° + ∠DBC = 180°
=> 142° + ∠DBC = 180°
∴ ∠DBC = 180° - 142° => 38°
OB = OD (radii)
∴ ∠DBC = ∠ODB = 52° (Angles opposite to equal sides are equal)
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