Question

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Find the HCF and LCM of the following given pairs of numbers by prime factorisation
method.
(i) 120,90 (ü) 50, 60 (ii) 37, 49​

Answer 1

Answer:

HCF of numbers = product of the smallest power of each common - prime factors of the number

LCM of number= product of greatest power of each prime factors of the number

(1) 120, 90

120⇒2×2×2×3×5=2

3

×3×5

90⇒2×3×3×5=2×3

2

×5

HCP⇒2×3×5=30

L.CM⇒2

3

×3

2

×5=360

(2) 50,60

50⇒2×5×5

=2×5

2

60=2×2×3×5=2

2

×3×5

HCF=2×5=10

LCM=2

2

×3×5

2

=300

(3) 37,49

37×1=37

49⇒7

2

HCF = 1

LCM = 37×7

2

=1086