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Find the HCF and LCMof the following given pairs of numbers by prime factorisation
(1) 120.90 (in) 50.60 (ii).37,49
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Step-by-step explanation:
HCF of numbers = product of the smallest power of each common - prime factors of the number
LCM of number= product of greatest power of each prime factors of the number
(1) 120, 90
120⇒2×2×2×3×5=23×3×5
90⇒2×3×3×5=2×32×5
HCP⇒2×3×5=30
L.CM⇒23×32×5=360
(2) 50,60
50⇒2×5×5
=2×52
60=2×2×3×5=22×3×5
HCF=2×5=10
LCM=22×3×52=300
(3) 37,49
37×1=37
49⇒72 HCF = 1
LCM = 37×72=1086
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