Math, asked by atlasbeam22, 1 year ago

do this if you can let do

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Answered by renuagrawal393
2

Answer:

 \frac{3}{\sqrt{2}  - 1}  \times  \frac{ \sqrt{2}  + 1 }{ \sqrt{2}  + 1}  \\  \rightarrow \:   \frac{3( \sqrt{2}  + 1)}{ {( \sqrt{2}) }^{2}  -  {1}^{2} }  \\ \rightarrow \:  \frac{3 \sqrt{2} + 3 }{1}

ii)  \frac{1}{7 - 4 \sqrt{3} }   \times  \frac{7 + 4 \sqrt{3} }{7 + 4 \sqrt{3} }  \\ \rightarrow \frac{7 + 4 \sqrt{3} }{ {7}^{2}  - ( {4 \sqrt{3}) }^{2} }  \\ \rightarrow \frac{7 + 4 \sqrt{3} }{49 - 48}  \\ \rightarrow \frac{7 + 4 \sqrt{3} }{1}

hope it helps you....

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