Question

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Ifp(x)=x2-5r-6, then find the values of p(1),p(2),px3),p(0),p(-1),p(-2), p(-3).​

Answer 1

Answer:

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Answer 2

Given, p(x)=x+3

Therefore, p(−x)=−x+3

Now, p(x)+p(−x)=(x+3)+(−x+3)=6