Math, asked by gottipatti, 8 months ago

Do this in a simple way.41th

Attachments:

Answers

Answered by VishnuPriya2801
6

Answer:-

According to BODMAS rule we can solve it first in,

B - bracket

O - of

D - Division

M - Multiplication

A - Addition

S - Subtraction.

 \frac{2}{5}  + 2 \frac{4}{9} { \div ((7 \frac{5}{12}  - 5 \frac{3}{4} ) \div 22 \frac{1}{2}  + 10 \times  \frac{5}{18}  )}\\  \\  =  \frac{2}{5}  +  \frac{22}{9}  \div( ( \frac{89}{12}  -  \frac{23}{4} )  \div  \frac{45}{2}  +  \frac{50}{18} ) \\  \\  =    \frac{18 + 110}{45}  \div ( \frac{89 - 69}{12}   \div  \frac{45}{2}  +  \frac{50}{18} ) \\  \\  =  \frac{128}{45}  \div ( \frac{20}{12}  \div  \frac{45}{2}  +  \frac{50}{18} ) \\  \\  =  \frac{128}{45}  \div ( \frac{20}{12}  \times  \frac{2}{45}  +  \frac{50}{18} ) \\  \\  =  \frac{128}{45}  \div ( \frac{2}{27}  +  \frac{25}{9} ) \\  \\  =  \frac{128}{45}  \div ( \frac{2 + 125}{7} ) \\  \\  =  \frac{128}{45}  \div  \frac{127}{27}  \\  \\  =  \frac{128}{45}  \times  \frac{27}{127}   \\  \\  =  \frac{384}{635}

(If we simplify it we will get the answer)

Similar questions