Question

do this please
for 7th class
I am from MGS school
mahabubnagar 7th c

Answer 1

Hey mate !!!!!

Here's your answer »»»»»»»»»»

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1. Given that ∆FEG is congruent to ∆LMN
Hence, by CPCT, we have —
FE = LM
EG = MN
FG = LN
angle L = angle F
angle N = angle G
angle E = angle M

2. Given that ∆ABC is congruent to ∆DEF
Hence,by CPCT, we have —
( i ) DE = AB
( ii ) angle E = angle B
( iii ) DF = AC
( iv ) angle F = angle C

3. ( i ) In ∆SUT & ∆RJK
SU = RJ (given)
ST = RK (given)
VT = JK (given)
Hence, ∆ SUT & ∆ RJK are congruent to each other by SSS condition

( ii ) In ∆EBI & ∆EIC
BC = EC (given)
BI = CI (given)
EI = EI (common)
Hence, ∆EBI & ∆EIC are congruent to each other by SSS condition

4. ( i ) ∆TUV is congruent to ∆XYZ
So, by CPCT, we have —

TU = XY
UV = YZ
VT = ZX
angle T = angle X
angle U = angle Y
angle V = angle Z

( ii ) ∆CDG is congruent to ∆RSW
So by CPCT, we have —

CD = RS
CD = SW
CG = WR
angle C = angle R
angle D = angle S
angle G = angle W

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You may also refer the attachment
Hope this helps
@PoojaBBSR