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Radius of the cylindrical oilcan is 4m.
Volume of the oilcan is 1408kl.
Volume of the oilcan = πr^2h
= 1408 = 22/7×4^2×h
= 1408 = 22/7×16h
= 1408×7/22= 16h
=64×7 = 16h
=64×7/16 = h
=28m = h
Therefore the height is 28m
Mark it brainliest plzzzz
Volume of the oilcan is 1408kl.
Volume of the oilcan = πr^2h
= 1408 = 22/7×4^2×h
= 1408 = 22/7×16h
= 1408×7/22= 16h
=64×7 = 16h
=64×7/16 = h
=28m = h
Therefore the height is 28m
Mark it brainliest plzzzz
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