Question

do this Q pls...!! ​

Answer 1

Answer:

183.6kJ/mol

Explanation:

Enthalpy of decomposition = -(enthalpy of formation )

Standard Enthalpy of decomposition=-(-91.8)

=+91.8kJ/mol

Now 34 g NH3= 34/17 moles NH3

(since moles=given mass/molar mass)

=2 moles NH3

For 1 mole enthalpy of decomposition=91.8

(Since standard enthalpy is for 1 mole)

For 2 moles enthalpy =2×91.8=183.6kJ/mol