Question

Do this question by Equation of motion

Questions:- an object of mass 200 gram is moving along a circular path of radius 1m. It completes to revolution of circular Pathin 22 seconds with constant speed. Then find out:-

1) Time period of circular path
2) Frequency of circular path
3) Speed of particle​

Answer 1

Answer:-

Given:-

Mass=200gram

R = 1

Time = 22 second

Answer:-

i) Time period us 22 second ( as it is given )

ii) in one sec. no of revolution = 1/22 = 0.0454 .

iii) Speed = Distance / Time

= 2πr / 22

= 2/22 X 22/7 X 1

=2/7 m/s

= 0.2857 m/s

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