Question

do this question if u do i will mark ur answer

Answer 1

Heya,

According to the question,

Object distance (u) = -20 cm

Radius of curvature (R) = 20 cm

Focal length (f) = 20/2 = 10 cm

Image distance (v) = ?

Lens formula.

=> 1/v - 1/u = 1/f

=> 1/v = 1/f + 1/u

=> 1/v = 1/10 - 1/20

=> 1/v = (2 - 1)/20

=> 1/v = 1/20

=> v = 20

As, the distance of image is positive so the,

Nature of image = Virtual and erect, same size as that of object.

Position of the image = 20 cm

Hope this helps....:)