do this question it's coming on board exam of science 2019 the best answer will get good point and brain list from me
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a) We would join three resistors of different values in series. Connect them with the help of a battery, ammeter and plug key. They play an important role in transmission of the current.
Thereafter, it is important to plug the key and note the ammeter reading. One should change the position of the ammeter to the relevant reading.
No reading is detected in the circuit, therefore the current flows through every part of the circuit.
b)i)
Given, Resistances->
R1 =24 ohm,
R2 =24ohm
R3 = 12ohm
Voltage(V) = 6v
Now,In case of R1 and R2 we get=>
1/Rn = 1/R1 + 1/R2
=>1/Rn = 1/24 + 1/24
=>1/Rn = 2/24ohm
=>Rn = 12 ohm.
Now, in case of Rn and R3 total reistances will be=>
Rg = Rn + R3
=>Rg = 12 + 12
=>Rg= 24 ohm.
Since we know that the same Current flows through each resistor in series.
Hence Current in 12 ohm resistor will be => I = V/Rg
=>I = 6/24
=>I = 1/4
=>I = 0.25 A
Hence the current through the 12 ohm resistor is 0.25ohm.
ii)
No, There will be no difference in Reading of ammeter A1 and A2 because there will be same Current flowing through each resistor as it is in Series combination.
Remember
1)Series Combination
-Net resistance is sum of all resistance in series.
-Rn= R1 + R2 + R3 +..... Rg
where,
Rn=> is the net resistance
R1,R2,R3=> are resistors in series and
Rg =>is the last resistor of the circuit.
-In these type of circuits,the net resistance is always greater than the highest value of resistance in the circuit.
2) Parallel Combination
- in this type of connection inverse of Net resistance is the sum of inverse of all other resistance in the circuit.
-1/Rn = 1/R1 + 1/R2 + 1/R3 +....1/Rp
where,
1/Rn=> is inverse for net resistance
1/Rp is the inverse of last resistance in the circuit.
-In this type of combination the net resistance is smaller than the smallest value of resistance in the combination.
a) We would join three resistors of different values in series. Connect them with the help of a battery, ammeter and plug key. They play an important role in transmission of the current.
Thereafter, it is important to plug the key and note the ammeter reading. One should change the position of the ammeter to the relevant reading.
No reading is detected in the circuit, therefore the current flows through every part of the circuit.
b)i)
Given, Resistances->
R1 =24 ohm,
R2 =24ohm
R3 = 12ohm
Voltage(V) = 6v
Now,In case of R1 and R2 we get=>
1/Rn = 1/R1 + 1/R2
=>1/Rn = 1/24 + 1/24
=>1/Rn = 2/24ohm
=>Rn = 12 ohm.
Now, in case of Rn and R3 total reistances will be=>
Rg = Rn + R3
=>Rg = 12 + 12
=>Rg= 24 ohm.
Since we know that the same Current flows through each resistor in series.
Hence Current in 12 ohm resistor will be => I = V/Rg
=>I = 6/24
=>I = 1/4
=>I = 0.25 A
Hence the current through the 12 ohm resistor is 0.25ohm.
ii)
No, There will be no difference in Reading of ammeter A1 and A2 because there will be same Current flowing through each resistor as it is in Series combination.
Remember
1)Series Combination
-Net resistance is sum of all resistance in series.
-Rn= R1 + R2 + R3 +..... Rg
where,
Rn=> is the net resistance
R1,R2,R3=> are resistors in series and
Rg =>is the last resistor of the circuit.
-In these type of circuits,the net resistance is always greater than the highest value of resistance in the circuit.
2) Parallel Combination
- in this type of connection inverse of Net resistance is the sum of inverse of all other resistance in the circuit.
-1/Rn = 1/R1 + 1/R2 + 1/R3 +....1/Rp
where,
1/Rn=> is inverse for net resistance
1/Rp is the inverse of last resistance in the circuit.
-In this type of combination the net resistance is smaller than the smallest value of resistance in the combination.
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