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Verify the statement proved above for p=2, p=5 and for a2 = 1,4,9, 25, 36, 49,64
and 81
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Theorem : Let p be a prime number. If p divides a² , (where a is a positive integer), then p divides a
Let say prime factors of a are
a = p₁ , p₂ , p₃ ........., pₓ where p₁ to pₓ are prime number
a = (p₁ × p₂ × p₃ ×.........× pₓ)
a² = (p₁ × p₂ × p₃ ×.........× pₓ) (p₁ × p₂ × p₃ ×.........× pₓ)
if p divides a² then it is one of (p₁ × p₂ × p₃ ×.........× pₓ)
as a = (p₁ × p₂ × p₃ ×.........× pₓ) so p divides a
Verification for
p = 2, p = 5 and for a square = 1, 4, 9, 25, 36, 49, 64 and 81.
2 is factor of 4 , 36 & 64
2 is factor of 2 , 6 & 8
5 is factor of 25
5 is a factor of 5 also
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