Do tree pa bird badhe h......... Ek bird kahte h agr tum mujhe 1 bird dedo to ma tumhare double ho jao gi........ Wahi dusri bird kaahte h ki agr tum mujhe ek bird dedo to ma tumhare barabar ho jao..........dono tree ma kitni bird ha?
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Suppose that bird A has x birds and bird B has y birds.
A/Q, x+1= 2(y-1) ⇒ x - 2y = -3 -----------(i)
and, y+1 = x-1 x- y = 2 -------------(ii)
Subtracting Eqn(i) - Eqn(ii)
-2y + y = - 3-2y = 5 Put the value of y in Eqn(ii) x = 2+ 5 = 7 Hence Bird A has 7 birds and Bird B has 5 birds.
A/Q, x+1= 2(y-1) ⇒ x - 2y = -3 -----------(i)
and, y+1 = x-1 x- y = 2 -------------(ii)
Subtracting Eqn(i) - Eqn(ii)
-2y + y = - 3-2y = 5 Put the value of y in Eqn(ii) x = 2+ 5 = 7 Hence Bird A has 7 birds and Bird B has 5 birds.
alammohdtayyabpaez6i:
thank you bhai
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(a) Magnesium chloride →MgCl2 (b) Calcium oxide →CaO (c) Copper nitrate →Cu(NO3)2 (d) Aluminium chloride →AlCl3 (e) Calcium carbonate →CaCO3
6.022×1023 102
× 0.051 molecules
= 3.011 × 1020 molecules of Al2O3 The number of aluminium ions (Al3+) present in one molecules of aluminium oxide is 2. Therefore, The number of aluminium ions (Al3+) present in 3.11 × 1020 molecules (0.051g) of aluminium oxide (Al2O3) = 2 × 3.011 × 1020 = 6.022 × 1020 1 mole of aluminium oxide (Al2O3) = 2 × 27 + 3 × 16 = 102g i.e., 102g of Al2O3 = 6.022 × 1023 molecules of Al2O3 Then, 0.051 g of Al2O3 contains =
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