Question

do (x-1) ^2+2(x+1)have real roots​

Answer 1

Step-by-step explanation:

x²+1+2x+2x+2=0

x²+4x+3=0

______= ___

1. 1

x²+4x+3=0

x²+4x=-3

x²+x=-3/4

4x²+4x=-3

4(x²+x)=-3

x²+x=-3/4

√x²=√-3-x/4²

x=-3-x/4