Do you agree?
3. A fuse bulb in a series connection does not
interrupt the flow of current in the circuit.
Answers
The circuit illustration shown below is a simple series circuit containing a battery, few wires and
two light bulbs. The flow of electricity is caused by excess electrons on the negative end of the
battery flowing towards the positive end, or terminal, of the battery. When the circuit is complete
electrons, flow from the negative terminal through the conducting wires to the bulbs (lighting it
up) and finally back to the positive terminal – in a continual flow.
A circuit that contains only one possible path for electron flow supplied by a common
voltage source.
A series circuit is wired with only one path for the current to flow through all the devices in a
row and back to the starting point. The same current flows through each part of a series circuit. If
the circuit is broken at any point there won’t be any current that will flow. In the above circuit,
electricity flows from the battery to each bulb, one at a time, in the order they are wired to the
circuit. In this case, if one of the bulbs blew out, the other bulb would not be able to light up
because the flow of electric current would have been interrupted. In the same way, if one of the
bulb was unscrewed, the current flow to both the bulbs would be interrupted. If the circuit were a
string of light bulbs, and one burned out, the remaining bulbs would also turn off.
yes I will agree
with you statement