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3 points
Imported
15] Side of a rhombus is 13 cm and one of the diagonal is 24 cm. Find the
length of the other diagonal *
A
M
B
D
Answers
Step-by-step explanation:
Answer
24cm...
Solution
Let ABCD is a Rhombus where E is a point there both diagonals intersect each other.
Given
Lengths AD = 13cm
\begin{gathered}Diagonals = 10cm \\ \\ BD = 2MD \\ \\ MD = \frac{1}{2} \times 10 \\ \\MD = 5\end{gathered}
Diagonals=10cm
BD=2MD
MD=
2
1
×10
MD=5
From property of Rhombus.
Diagonal of Rhombus bisect each other at 90° angles.
In ∆ AMD
Using Pythagoras theorem.
\begin{gathered}AD^2 = AM^2 + MD^2 \\ \\ 13^2 = Am^2 + 5^2 \\ \\ Am^2 = 13^2 - 5^2 \\ \\ Am^2 = 169 - 25 \\ \\ Am^2 = \sqrt{144} \\ \\ = \sqrt{12 \times 12} \\ \\ Am = 12cm\end{gathered}
AD
2
=AM
2
+MD
2
13
2
=Am
2
+5
2
Am
2
=13
2
−5
2
Am
2
=169−25
Am
2
=
144
=
12×12
Am=12cm
BD = 2Am
BD = 2 × 12cm
BD = 24 cm.
Therefore the lengths of diagonals of Rhombus are 24cm
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Answer:
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docs.google.
3 points
Imported
15] Side of a rhombus is 13 cm and one of the diagonal is 24 cm. Find the
length of the other diagonal *
A
M
B
D
