Question

Doctor hqs prescribed a lens having power + 1.5 D.what will be the focal length of the lens? what is the type of the lens and what must be defect of vision.

Answer 1

Hey mate ☺️

Power = +1.5 D

Focal length =

$\frac{1}{power}$

$f \: = \frac{1}{1.5} = \frac{10}{15} \\ = \frac{2}{3} = 0.666 \\ = 0.67m$

The Convex lens is used.

The defect of vision is hypermetropia.

I Hope it helps you ☺️✌️✌️

Answer 2

Here's your answer mate:

P=+1.5D
f=?

Focal length of the lens,
f=1/P
=1/1.5D
=10/15m

=0.6667m
=0.67m

P is positive.

This shows that the lens is convex. This defect of vision is Farsightedness ( Hypermetropia)