doctors advice brisk walking in the morning to remain fit if a person had walked 1kmhr faster he would have taken 15min less to walk 3km? find the orignal rate of his walking
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Let the original speed be x km/hr
Distance = 3 km
time = 3/x
New Speed = x+1 km/hr
time = (3/x)-1/4 hr
= (9/4x)
Distance = 3 km
(x+1) = 3/(9/4x)
x+1 = 4x/3
3x+3 = 4x
x = 3
hence the original rate of walking is 3 km per hour.
Distance = 3 km
time = 3/x
New Speed = x+1 km/hr
time = (3/x)-1/4 hr
= (9/4x)
Distance = 3 km
(x+1) = 3/(9/4x)
x+1 = 4x/3
3x+3 = 4x
x = 3
hence the original rate of walking is 3 km per hour.
Russy:
samr hre ..3 and _4
Answered by
4
x=3andx=_4
final eqn appers to be (x+4)(x-3)=0
final eqn appers to be (x+4)(x-3)=0
as the values of x are 3 & -4 . so the speed will be 3 only as speed can be never negative....
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