Physics, asked by anujjaiswal5651, 1 year ago

Does anybody know how to derive the Bolzman equation for photon distribution function in the presence of tensor perturbations?

Answers

Answered by 77dhanush
0

Classical equilibrium statistical mechanics is described by the full N-body distribution,

f

0

(x1

, . . ., xN ; p1

, . . ., pN ) =

Z

−1

N ·

1

N!

e

−βHˆN (p,x) OCE

Ξ−1

·

1

N!

e

βµN e

−βHˆN (p,x) GCE .

(5.1)

We assume a Hamiltonian of the form

N =

X

N

i=1

p

2

i

2m

+

X

N

i=1

v(xi

) +X

N

i<j

u(xi − xj

), (5.2)

typically with v = 0, i.e. only two-body interactions. The quantity

f

0

(x1

, . . . , xN ; p1

, . . ., pN )

d

dx1 d

dp1

h

d

· · ·

d

dxN d

dpN

h

d

(5.3)

is the probability, under equilibrium conditions, of finding N particles in the system, with particle #1 lying within

d

3x1 of x1 and having momentum within d

dp1 of p1

, etc. The temperature T and chemical potential µ are constants,

independent of position. Note that f({xi

}, {pi

}) is dimensionless.

Nonequilibrium statistical mechanics seeks to describe thermodynamic systems which are out of equilibrium,

meaning that the distribution function is not given by the Boltzmann distribution above. For a general nonequilibrium

setting, it is hopeless to make progress – we’d have to integrate the equations of motion for all the constituent

particles. However, typically we are concerned with situations where external forces or constraints are imposed

over some macroscopic scale. Examples would include the imposition of a voltage drop across a metal, or a temperature

differential across any thermodynamic sample. In such cases, scattering at microscopic length and time

scales described by the mean free path ℓ and the collision time τ work to establish local equilibrium throughout the

system. A local equilibrium is a state described by a space and time varying temperature T (r, t) and chemical

potential µ(r, t). As we will see, the Boltzmann distribution with T = T (r, t) and µ = µ(r, t) will not be a solution

to the evolution equation governing the distribution function. Rather, the distribution for systems slightly out of

equilibrium will be of the form f = f

0 + δf, where f

0 describes a state of local equilibrium.

We will mainly be interested in the one-body distribution

f(r, p;t) = X

N

i=1

δ

xi

(t) − r) δ(pi

(t) − p

 

= N

Z Y

N

i=2

d

dxi d

d

pi

f(r, x2

, . . . , xN ; p, p2

, . . . , pN ;t) .

(5.4)

In this chapter, we will drop the 1/~ normalization for phase space integration. Thus, f(r, p, t) has dimensions of

h

−d

, and f(r, p, t) d

3

r d3p is the average number of particles found within d

3

r of r and d

3p of p at time t.

In the GCE, we sum the RHS above over N. Assuming v = 0 so that there is no one-body potential to break

translational symmetry, the equilibrium distribution is time-independent and space-independent:

f

0

(r, p) = n (2πmkBT )

−3/2

e

−p

2/2mkBT

, (5.5)

where n = N/V or n = n(T, µ) is the particle density in the OCE or GCE. From the one-body distribution we cancompute things like the particle current, j, and the energy current, jε

:

j(r, t) = Z

d

d

p f(r, p;t)

p

m

(5.6)

(r, t) = Z

d

d

p f(r, p;t) ε(p)

p

m

, (5.7)

where ε(p) = p

2/2m. Clearly these currents both vanish in equilibrium, when f = f

0

, since f

0

(r, p) depends

only on p

2 and not on the direction of p. In a steady state nonequilibrium situation, the above quantities are

time-independent.

Thermodynamics says that

dq = T ds = dε − µ dn , (5.8)

where s, ε, and n are entropy density, energy density, and particle density, respectively, and dq is the differential

heat density. This relation may be case as one among the corresponding current densities:

jq = T js = jε − µ j . (5.9)

Thus, in a system with no particle flow, j = 0 and the heat current jq

is the same as the energy current jε

.

When the individual particles are not point particles, they possess angular momentum as well as linear momentum.

Following Lifshitz and Pitaevskii, we abbreviate Γ = (p, L) for these two variables for the case of diatomic

molecules, and Γ = (p, L, nˆ · L) in the case of spherical top molecules, where nˆ is the symmetry axis of the top.

We then have, in d = 3 dimensions,

dΓ =

d

3p point particles

d

3p L dL dΩL diatomic molecules

d

3p L2 dL dΩL

d cos ϑ symmetric tops ,

(5.10)

where ϑ = cos−1

(nˆ · Lˆ ). We will call the set Γ the ‘kinematic variables’. The instantaneous number density at r is

then

n(r, t) = Z

dΓ f(r, Γ;t) . (5.11)

One might ask why we do not also keep track of the angular orientation of the individual molecules. There are

two reasons. First, the rotations of the molecules are generally extremely rapid, so we are justified in averaging

over these motions. Second, the orientation of, say, a rotor does not enter into its energy. While the same can be

said of the spatial position in the absence of external fields, (i) in the presence of external fields one must keeptrack of the position coordinate r since there is physical transport of particles from one region of space to another,

and (iii) the collision process, which as we shall see enters the dynamics of the distribution function, takes place

in real space.

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