Does anyone know how to do this ..pic given down ..pls help
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AB^2 +BC^2= AC^2
4^2 + 3^2= √25= 5cm
BY MID-POINT THEOREM--
PQ//AC. and. PQ=1/2AC
PQ=1/2 × 5= 2.5cm
4^2 + 3^2= √25= 5cm
BY MID-POINT THEOREM--
PQ//AC. and. PQ=1/2AC
PQ=1/2 × 5= 2.5cm
Answered by
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in this figure
DC=4, then DQ = 2
DA = 3, then DP = 3/2
in ∆DQP
PQ^2 = 3^2 + (3/2)^2
= 9 + 9/4
= 45/4
PQ = √45/2
= 3√5/2
DC=4, then DQ = 2
DA = 3, then DP = 3/2
in ∆DQP
PQ^2 = 3^2 + (3/2)^2
= 9 + 9/4
= 45/4
PQ = √45/2
= 3√5/2
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