does anyone know how to solve this integretion ?
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Put
√x=t
X=t^2
So int(logt)^2
Using by parts
=x(logx)
2
−2∫x.logx.
x
1
dx
=x(logx)
2
−2∫logxdx
=x(logx)
2
−2[xlogx−x]
=x[(logx)
2
−2logx+2].
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