Question

Does anyone know the answer ​

Answer 1

ans is 4

dy/dx

4×0/4×2

0/8

Answer 2

Answer:

x^3 - 2xy + y^3 = 8

differentiating w.r.t x, we get

3x^2 - 2(xdy/dx + y) + 3y^2dy/dx = 0

3x^2 - 2x dy/dx - 2y + 3y^2 dy/dx = 0

dy/dx (3y^2 - 2x) = 2y - 3x^2

dy/dx = (2y - 3x^2)/(3y^2 - 2x)

putting x = 2, y = 0, we get

dy/dx = (0-3*4)/(0-2*2)

= -12/-4

= 3

first option