Question

Does anyone know the solution of this
Equation :- (y-8)(3y-4) =

Answer 1

Hope this will help you

Answer 2

Answer:

(y-8)(3y-4)

=3y^2-4y-24y+32

=3y^2-28y+32

Applying shreedharacharya formula,

y=(-b+√b^2-4ac)1/2a

Or

(-b-√b^2-4ac)1/2a

Here,y=(28+√784-384)1/6

Or

(28-√784-384)1/6

=>y=(28+20)1/6 or (28-20)1/6

=>y=24/3 or4/3