Does anyone know the solution to this? 3(2y+3)=4y+3
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Answer:
Answer:
\begin{gathered}3(2y + 3) = 4y + 3 \\
6y + 9 = 4y + 3 \\
6y - 4y = 3 - 9 \\
2y = - 6 \\
y = \frac{ - 6}{2} \\
y = - 3\end{gathered}3(2y+3)=4y+36y+9=4y+36y−4y=3−92y=−6y=2−6y=−3
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