Math, asked by AnkitKumarBhagat, 1 year ago

Does in this figure,AB=BC or not and why?

Attachments:

AnkitKumarBhagat: 10

sandy09: oo

AnkitKumarBhagat: n u

sandy09: oo

AnkitKumarBhagat: 00 it's a class

sandy09: me in 9 class

AnkitKumarBhagat: ok great

sandy09: yaa

AnkitKumarBhagat: good luck for future

sandy09: same to u

Answers

Answered by Anonymous

yes ab = bc.
have read theorem tangent is perpendicular to the radius

now congruent these ∆s by (SAS)

AnkitKumarBhagat: to prove them similar three proofs are needed but here are only 2

sandy09: wait

AnkitKumarBhagat: ok

Answered by kshitijNGU

Hope it will help you

Attachments:

AnkitKumarBhagat: AO and CO are not the radius

kshitijNGU: u can also take it as a hypotenuse

AnkitKumarBhagat: By RHS rule?

sandy09: ya by rhs also and by asa also

sandy09: perpendicular angle and angle at the center are equal

AnkitKumarBhagat: RHS is possible but how asa?

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