Does in this figure,AB=BC or not and why?
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AnkitKumarBhagat:
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yes ab = bc.
have read theorem tangent is perpendicular to the radius
now congruent these ∆s by (SAS)
have read theorem tangent is perpendicular to the radius
now congruent these ∆s by (SAS)
to prove them similar three proofs are needed but here are only 2
wait
ok
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Hope it will help you
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AO and CO are not the radius
u can also take it as a hypotenuse
By RHS rule?
ya by rhs also and by asa also
perpendicular angle and angle at the center are equal
RHS is possible but how asa?
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