Physics, asked by saad5292, 4 months ago

does sin2wt+coswt represent simple harmonic motion​

Answers

Answered by sahilmeena030
0

Answer:

(a) SHM

The given function is:

sinωt−cosωt

=

2

[

2

1

sinωt−

2

1

cosωt]

=

2

[sinωt×cos

4

π

−cosωt×sin

4

π

]

=

2

sin(ωt−

4

π

)

This function represents SHM as it can be written in the form: a sin(ωt+ϕ) Its period is: 2π/ω.

(b) Periodic but not SHM

The given function is:

sin

3

ωt=1/4[3sinωt−sin3ωt]

The terms sin ωt and sin 3ωt individually represent simple harmonic motion (SHM). However, the superposition of two SHM is periodic and not simple harmonic.

Its period is: 2π/ω (LCM of time periods).

(c) SHM

The given function is:

3cos[

4

π

−2ωt]

=−3cos[2ωt−

4

π

]

This function represents simple harmonic motion because it can be written in the form: a cos(ωt+ϕ). Its period is: 2π/2ω=π/ω

(d) Periodic, but not SHM

The given function is cosωt+cos3ωt+cos5ωt. Each individual cosine function represents SHM. However, the superposition of three simple harmonic motions is periodic, but not simple harmonic.

Its period is LCM of the period of the three sinusoids = 2π/ω

(e) Non-periodic motion

The given function exp(−ω

2

t

2

) is an exponential function. Exponential functions do not repeat themselves. Therefore, it is a non-periodic motion.

(f) The given function 1+ωt+ω

2

t

2

is non-periodic.

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