Does spin affect the expression for a Bose-Einstein Condensate's critical temperature?
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You have to include that factor. The correct expression is
kBTc=[(2s+1)g3/2(1)]−2/3h22πm(NV)2/3kBTc=[(2s+1)g3/2(1)]−2/3h22πm(NV)2/3
where g3/2(1)=ζ(3/2)≃2.612g3/2(1)=ζ(3/2)≃2.612. If s=0s=0 your expression is retrieved
kBTc=[(2s+1)g3/2(1)]−2/3h22πm(NV)2/3kBTc=[(2s+1)g3/2(1)]−2/3h22πm(NV)2/3
where g3/2(1)=ζ(3/2)≃2.612g3/2(1)=ζ(3/2)≃2.612. If s=0s=0 your expression is retrieved
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