Does the escape velocity of a body from the earth depends upon the mass of the body explain
Answers
Surely it does…. The answer is a bit long, please bear with me.
There are 2 reasons why this happens.. let's list the connected parameter first.
F = GMm/r^2…….………..(1)
Classic equation for gravitational force…
Let's rewrite this into our common weight equation.
F = mg………………..(2)
Now, from these two equations, if we set the mass of the body we'll throw as a constant, we can talk about the reasons more clearly.
Now, the remaining parameters in the 2 equations are
From (1), r
From (2), g
(1) We surely understand that gravitational force is inverself proportional to the distance between the centers of the two bodies.
Therefore, though very minor (since the heights and depths on the earth barely stand out against the hugeness of our planet), the location affects escape velocity. (This effect is negligible for all practical purposes.)
(2) It is a well known fact that gravity produced by our planet is not symmetric. Instead there are significant difference in the gravitational pull in different locations. Link: Mapping Earth's Gravity
These differences are in the range of 9.78 to 9.83 ms-2. This too isn't a a huge difference unless, (remember our body's constant mass?) the mass of our body is very large. In that case, we add less than 0.05 N/kg of force to the escape velocity's equation. This number does play a significant role as it can affect fuel quantities needed for rocket launches.