Question

does the point(1,2) lies on the graph 2x-3y+4=0

Answer 1

Hey friend !!!!!

•°• Here's your answer •°•

Equation => 2x - 3y + 4 = 0

=> 2x + 4 = 3y

So, let's find that the point ( 1, 2 ) lies on the graph or not??

Equation => 2x + 4 = 3y

Put x = 1

=> 2 ( 1 ) + 4 = 3y

=> 2 + 4 = 3y

=> 6 = 3y

=> 6/3 = y

=> 2 = y

Yeah, ( 1, 2 ) lies on the graph.

Any problem regarding the solution, feel free to ask me in the comment section.

Hope it satisfies you ☆▪☆

Thanks ^_^

☆ Be Brainly ☆

Answer 2

$\textbf{Answer}$

Given equation is,

2x - 3y + 4 = 0

We know that the point (a,b) lies on the graph 2x-3y+4=0 only when LHS of the equation becomes RHS of the equation after replacing x by a and y by b.

Given point is (1,2)

So this point will lie on graph 2x - 3y + 4 = 0 if,
x=1 and y=2 and LHS = RHS.

Lets put the value of x=1 and y=2 in the equation,

LHS = 2x - 3y + 4
=> LHS = 2×1 - 3×2 + 4
=> LHS = 2 - 6 + 4
=> LHS = 0

&

RHS = 0

=> $\textbf{LHS = RHS}$

So point (1,2) satisfies the equation of the graph 2x-3y+4=0.


$\textbf{So the point (1,2) lies on the graph 2x-3y+4=0}$


$\textbf{Hope It Helps}$
$\textbf{Thanks}$