Question

Does the polynomial a4+ 4a2+ 5 =

0 have real zeroes?​

Answer 1

Step-by-step explanation:

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Answer 2

Let a² = x.

Now, the polynomial becomes,

x2 + 4x + 5

Comparing with ax² + bx + c,

Here, b² – 4ac

= 42 – 4(1)(5)

= 16 – 20

= ( -4 )

So, D = b² – 4ac < 0

As the discriminant (D) is negative, the given polynomial does not have real roots or zeroes.