does the polynomial f(x)=xsqare+1 have real zeroes?justifi
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0
Answer:
does not factor
Step-by-step explanation:
Answered by
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Here is your ans.
X²+1=0
x²=-1
x=√-1
x=i ∉R
(or)
x=-b± √b²-4ac/2a
here
a=1
b=0
c=1
x=0 ± √0-4/2(1)
=0±√-4/2
=±2i/2
= +i or -i
i belongs to complex number
So x square +1 have no zeros .
Hope it’ll help uhh..!
X²+1=0
x²=-1
x=√-1
x=i ∉R
(or)
x=-b± √b²-4ac/2a
here
a=1
b=0
c=1
x=0 ± √0-4/2(1)
=0±√-4/2
=±2i/2
= +i or -i
i belongs to complex number
So x square +1 have no zeros .
Hope it’ll help uhh..!
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